Symbolism in English Literature - 2444 Words

Archetypal figures present in Chaucer’s â€Å"The Miller’s Tale† By Josà © Luis Guerrero Cervantes According to Swiss psychiatrist Carl Jung, an archetype is a symbolic formula that begins to work wherever there are no conscious ideas present. They are innate universal psychic dispositions that form the substrate from which the basic themes of human life emerge[1]. The archetype is experienced in projections, powerful affect images, symbols, moods, and behavior patterns such as rituals, ceremonials and love. Jung[2] compared the archetype, the pre-formed tendency to create images, to a dry river bed. Rain gives form and direction to the flow, we name the river, but it is never a thing located in any place, it is a form but never the same,†¦show more content†¦And she had plucked her eyebrows into bows, Slenderly arched they were, and black as sloes; And a more truly blissful sight to see She as than blossom on a cherry-tree, [†¦] Her mouth was sweet as mead or honey –say A hoard of apples lying in the hay. Skittish she was, and jolly as a colt, Tall as a mast and upright as a bolt Out of bow. [†¦] She was a daisy, O a lollypop For any nobleman to take to bed Or some good man of yeoman stock to wed.[9] Everything in her is lovely. Chaucer centers his attention on the physical description and little is said about her character. However, the adjectives â€Å"skittish†, â€Å"jolly†, â€Å"tall† and â€Å"upright† describe her as someone irreproachable in any sense. After she falls in love with Alison, all the marvelous image of Alison disappears when she decides to play a cruel joke to Absalon: Absalon started wiping his mounth dry. Dark was the night as pitch, as black as coal, And at the window out she put her hole, And Absalon, so fortune framed the farce, Put up his mouth and kissed her naked arse Most savorously before he knew of this.[10] As it can be observed, Alison’s attitude changes dramatically after meeting Nicholas (the object of desire). This desire unleashes those feelings that are the negative counterpart of the male â€Å"Animus†. â€Å"Eve† development of â€Å"Anima† helps toShow MoreRelatedSamuel Clemens : The Father Of American Literature1614 Words   |  7 PagesAmerican Literature is a literary genre that is one of the many branches formed from the much broader literary genre, English Literature. Stories such as The Great Gatsby, Of Mice and Men, The Crucible, and The Adventures of Tom Sawyer are all popular examples of American Literature. Many of the most well-known written works of American Literature can be funneled back to one person, Samuel Clemens. Many people might say, who is Samuel Clemens? However, if they are informed of his â€Å"pen† name, theyRead MoreEnglish Language Arts Lesson Plan: Edgar Allen Poes The Raven618 Words   |  3 PagesEnglish Langua ge Arts Lesson In this activity, I have planned a lesson reviewing the infamous poem, The Raven by Edgar Allen Poe. The lesson itself is intended to follow the Alabama State Standards for Seventh Grade Language Arts. According to the state standards for literature, the form, theme, tone, and syntax of poems must be analyzed and understood, as stated in standards one through 6 (Alabama Learning Exchange, 2010). Thus the following activities are meant to be undertaken by studentsRead MoreSir Gawain and The Green Knight Essay1109 Words   |  5 Pagesthree is linked with magic in folklore and with the Trinity in Christian symbolism† (Blanch 4). There are many things within this narration which resemble symbolism of a much larger meaning. The Gawain Poet uses the green girdle, the number three and the pentangle as symbolism with in the story. The pentangle symbolizes the virtues to which Gawain aspires and the faultless in his five senses. The green girdle’s symbolism changes over the course of the narrative, the color is linked to the greenRead MoreGeoffrey Chaucer s Impact On Literature1231 Words   |  5 PagesGeoffrey Chaucer’s Impact on Literature: English poet Geoffrey Chaucer is acclaimed to be one of the best and most influential poets in history. Geoffrey Chaucer wrote several famous literary works in what is called middle English. Geoffrey Chaucer was born in 1340 in London, England. Over the course of Chaucer’s life, he entered and exited several different social classes. He began to write his most known pieces when he became a public servant to Countess Elizabeth of Ulster in 1357. He diedRead MoreStevenson and Conrad: The Duality of Human Nature 949 Words   |  4 PagesConrad also employs the literary device of symbolism to further display the theme, the duality of human nature in his novella Heart of Darkness. Three major examples of symbolism are evident in this novella. These examples include, light and dark, the Congo River, and ivory. Similar to Stevenson, Conrad uses light and dark symbolism throughout his novella. Yet curiously in Heart of Darkness, light does not symbolize genuine goodness nor doe s dark symbolize pure calamity. Marlow proves this when heRead MoreJane Eyre vs Wide Sargasso Sea Essay example1635 Words   |  7 Pagesï » ¿Tyler Perimenis Professor Mathews English 2301W 21 October 2014 Symbolism through Theme Of Jane Eyre and Wide Sargasso Sea â€Å"To produce a mighty book, you must choose a mighty theme. No great and enduring volume can ever be written on the flea, though many there be that have tried it,† stated Herman Melville. As implied, without theme, no novel can be considered â€Å"mighty† or have any depth. Theme is essential in any work of art. Jane Eyre is a novel by Charlotte Brontà « that takes the readerRead MoreHow The Cask of Amontillado Uses Symbolism and Irony1291 Words   |  6 Pages Often, writers use symbolism to describe an object with more clarity to the reader. It provides additional layers of meaning to a text. Symbolism is not only important in literature but is also important in everyday life. For instance, symbolism is found in colors, objects, and on flowers. For example a rose can represent love and romance. Symbolism is used in literature, movies, and even on street signs. Such as the colors in the street light: red means stop, yellow means slow down, and the greenRead MoreSymbolism in the Masque of the Red Death by Edgar Allen Poe1655 Words   |  7 PagesSymbolism in The Masque of the Red Death The Masque of the Red Death is a short story written by acclaimed literary author, Edgar Allen Poe. The story is an emphasis on the fact that there is no avoiding death, no matter how hard you try, which is the overall theme. The text tells the story of Prince Prospero whose town is being plagued by the dreaded Red Death. He attempts to avoid the plague by inviting 1,000 of his closest friends, all of which are variably different, to isolate themselvesRead More Comparing Symbols and Symbolism in Blue Hotel, Black Cat, Night, Alfred Prufrock, Red Wheelbarrow1620 Words   |  7 PagesColor Symbolism in Blue Hotel,  Black Cat, Night,  Alfred Prufrock,  Red Wheelbarrow      Ã‚  Ã‚   Symbolism of colors is evident in much of literature. The Blue Hotel by Stephen Crane, The Black Cat of Edgar Allan Poe, Night by William Blake, The Love Song of J. Alfred Prufrock by T. S. Eliot, and The Red Wheelbarrow by William Carlos Williams encompass examples of color symbolism from both the prose and the poetry of literature. When drawing from various modes of psychology, interpretationsRead MoreHow Theme Shapes a Story632 Words   |  3 PagesRunning Head: Theme How Theme Shapes a Story By Trina Carr English 125 Instructor: Clifton Edwards Running Head: Theme page 1 Like many people who haven’t studied literature, if someone asked me what the theme of a story was, I would have given a synopsis of the story detailing the actions and characters in it. As I have come to learn, theme is much more than a distilled retelling of a story

Essay on The Abuse of the Poor in Oliver Twist by Charles...

The Abuse of the Poor in Oliver Twist by Charles Dickens Charles Dickens shows notable amounts of originality and morality in his novels, making him one of the most well-known novelists of the Victorian Era and preserving him through his great novels and short stories. One of the reasons his work has been so popular is because his novels reflect the issues of the Victorian era, such as the great disregard of many Victorians to the situation of the poor. The reformation of the Poor Law in 1834 brings even more unavoidable problems to the poor. The Poor Law of 1834 allowed the poor to receive public assistance only through established workhouses, causing those in debt to be sent to prison. Workhouses were in existence before 1834, but†¦show more content†¦Dickens uses satire in Oliver Twist to protest what the English believe are charitable solutions to the increasing poverty rates, extensive child labor in workhouses. Dickens witnesses an injustice happening in Englands workhouses and works to make societys views of the abuse of c hildren change, but by this time, the horrors of the workhouse were so established in the English scene that they were destined to become part of the British social legend Those in favor of the workhouse supported it because it efficiently sealed off the poor, decreased population growth by separating husbands and wives, and shamed the needy(Epstein 94) Because of the Poor Law of 1834, the young children suffered more than the able bodied benefitted, so through Dickens career, he becomes preoccupied with the use and abuse of the Poor Laws. Through satire, Dickens explores the relationships between the paupers and the masters of the workhouse. Satire is used to portray the cruelty, sufferings, and injustice in the workhouses especially through Mr. Bumble, Mrs. Corney, and Oliver, characters that play a significant role in the message of child abuse in the workhouses. Through these characters and their actions, Dickens is able to reveal how ordinary workhouse masters treat their p aupers. Mr. Bumble and Mrs. Corney are stereotypes of the heartless employers who overuse their power on the workhouse children. Mr. Bumble is the corruptShow MoreRelatedEssay on Oliver Twist901 Words   |  4 PagesOliver Twist A Criticism of Society or a Biography With all of the symbolism and moral issues represented in Oliver Twist, all seem to come from real events from the life of its author, Charles Dickens. The novel’s protagonist, Oliver, is a good person at heart surrounded by the filth of the London streets, filth that Dickens himself was forced to deal with in his everyday life. It’s probable that the reason Oliver Twist contains so much fear and agony is because it’s a reflection of occurrencesRead MoreAnalysis Of Charles Dickens s Oliver Twist 1539 Words   |  7 Pages​Charles Dickens illustrates how people facing poverty are treated as criminals by the Victorian society and may cause them to be forced down the path of crime. He demonstrates this theory throughout his novel Oliver Twist. Oliver Twist is a novel about a ten year old orphan in the nineteenth century who is forced into labour at a workhouse. Dickens highlights the conditions of the workhouse to display the struggle one bares in order t o survive. He uses the characters Oliver and Nancy to demonstrateRead MoreCharles Dickens Biography1626 Words   |  7 Pages and perplexed characters Oliver Twist and David Copperfield. He proves that he is a product of the Victorian era as he brings attention to the childhood cruelty, the less fortunate in an English society, and the unwealthy dysfunctional families of the early Victorian time period. Charles Dickens reflects these and other issues as he brings to life the realism of writing. While others were writing about the way things should be, rather than the way things were, Dickens was challenging these ideasRead MoreChild Exploitation During The Victorian Era1583 Words   |  7 PagesEnglish novelist Charles Dickens was born into an underprivileged family during the Victorian Era. His father was jailed and Dickens was sent to work in a factory at the age of twelve (Dutta 1). It can be deduced because of Dickens’s formative years, one much like Oliver’s f rom Oliver Twist, Dickens felt the need to criticize the conditions of his time period (Diniejko). The novel is well known for being about an orphaned child who starts his life in an orphanage workhouse, gets involved in aRead MoreThe Evidence Of Unbound Loyalty1746 Words   |  7 PagesEvidence of Unbound Loyalty in Oliver Twist As young Oliver, ill-treated and hungry, approaches his masters saying â€Å"Please, sir, I want some more† (Dickens 11), Charles Dickens enthralls his readers in the harsh, twisted journey of Oliver Twist. Through a series of exciting events full of abuse, loyalty, hatred, and love, Dickens portrays the overlooked difficulties of the poor, lower class that Oliver Twist’s action-packed life has been subject to. Some of Dickens most loved characters, includingRead MoreCharles Dickens s A Christmas Carol1923 Words   |  8 PagesEnglish author Charles Dickens has written many well known novels such as Oliver Twist and A Christmas Carol, of which both have a recurring theme: the expectations of society. During the Victorian Era, England was over populated and had terrible living conditions, with an enormous gap between the rich and the poor. Generally, people during the Victorian Era were not allowed to talk about things such as sex and crime, and had to live by strict so cial rules set by society. With the social disparitiesRead MoreSocial Reform in Charles Dicke906 Words   |  4 PagesSocial Reform in Dickens In Oliver Twist and Great Expectations by Charles Dickens, both main characters refuse to except the poor hand the world has dealt them. Pip and Oliver reach a great epiphany in regards to social injustice, and in turn rebel against the system that oppresses them. They are tired of being mistreated and neglected, and thusly decide to make a stand. Charles Dickens exhibits to us through Oliver and Pip that the revolt of the weak against the strong results from theRead MoreEssay on The Portrayal of the Under Classes in Oliver Twist1171 Words   |  5 PagesThe Portrayal of the Under Classes in Oliver Twist During the early 1800s a great number of people were living in extreme poverty. Dickens had grown up in a poor family. As his childhood was so awful he wrote the novel Oliver twist as a protest towards the way the poorer community were treated. This period of time was torrid for the underclass population, particularly the children. Orphaned children had only two choices. They could both live and work in workhousesRead MoreAnalysis Of The Book Oliver Twist 1298 Words   |  6 PagesOliver Twist Recently for a project for an English class, the students were asked to do an assignment of reading Oliver Twist. This is the first time most of the students had read the novel. Some of the students prefer to engage their learning by watching the movies of novels instead of reading the material. Surprisingly, most of the students enjoyed the late Charles Dickens. They greatly adored all of the plot twists and how they, the readers, were always on their toes until the next chapterRead MoreEssay on Social Reform In Charles Dicke899 Words   |  4 Pages Social Reform in Dickens nbsp;nbsp;nbsp;nbsp;nbsp;In Oliver Twist and Great Expectations by Charles Dickens, both main characters refuse to except the poor hand the world has dealt them. Pip and Oliver reach a great epiphany in regards to social injustice, and in turn rebel against the system that oppresses them. They are tired of being mistreated and neglected, and thusly decide to make a stand. Charles Dickens exhibits to us through Oliver and Pip that the revolt of the weak against the

Edexcel Maths Fp2 Paper Free Essays

Paper Reference(s) 6667 Edexcel GCE Further Pure Mathematics FP1 Advanced Level Specimen Paper Time: 1 hour 30 minutes Materials required for examination Answer Book (AB16) Graph Paper (ASG2) Mathematical Formulae (Lilac) Items included with question papers Nil Candidates may use any calculator EXCEPT those with the facility for symbolic algebra, differentiation and/or integration. Thus candidates may NOT use calculators such as the Texas Instruments TI-89, TI-92, Casio CFX-9970G, Hewlett Packard HP 48G. Instructions to Candidates In the boxes on the answer book, write the name of the examining body (Edexcel), your centre number, candidate number, the unit title (Further Pure Mathematics FP1), the paper reference (6667), your surname, initials and signature. We will write a custom essay sample on Edexcel Maths Fp2 Paper or any similar topic only for you Order Now When a calculator is used, the answer should be given to an appropriate degree of accuracy. Information for Candidates A booklet ‘Mathematical Formulae and Statistical Tables’ is provided. Full marks may be obtained for answers to ALL questions. This paper has eight questions. Advice to Candidates You must ensure that your answers to parts of questions are clearly labelled. You must show sufficient working to make your methods clear to the Examiner. Answers without working may gain no credit. This publication may only be reproduced in accordance with London Qualifications Limited copyright policy. Edexcel Foundation is a registered charity.  ©2003 London Qualifications Limited 1. Prove that a (r r =1 n 2 – r -1 = ) 1 (n – 2)n(n + 2) . 3 (5) 2. 1 f ( x ) = ln x – 1 – . x (a) Show that the root a of the equation f(x) = 0 lies in the interval 3 lt; a lt; 4 . (2) (b) Taking 3. 6 as your starting value, apply the Newton-Raphson procedure once to f(x) to obtain a second approximation to a. Give your answer to 4 decimal places. (5) 3. Find the set of values of x for which 1 x gt; . x -3 x -2 (7) 4. f ( x ) ? 2 x 3 – 5 x 2 + px – 5, p I ?. The equation f (x) = 0 has (1 – 2i) as a root. Solve the equation and determine the value of p. (7) 5. (a) Obtain the general solution of the differential equation dS – 0. 1S = t. dt (6) (b) The differential equation in part (a) is used to model the assets, ? S million, of a bank t years after it was set up. Given that the initial assets of the bank were ? 200 million, use your answer to part (a) to estimate, to the nearest ? illion, the assets of the bank 10 years after it was set up. (4) 2 6. The curve C has polar equation r 2 = a 2 cos 2q , -p p ? q ? . 4 4 (a) Sketch the curve C. (2) (b) Find the polar coordinates of the points where tangents to C are parallel to the initial line. (6) (c) Find the area of the region bounded by C. (4) 7. Given that z = -3 + 4i and zw = -14 + 2i, find (a) w in the form p + iq where p and q are real, (4) (b) the modulus of z and the argument of z in radians to 2 decimal places (4) (c) the values of the real constants m and n such that mz + nzw = -10 – 20i . (5) 3 Turn over 8. (a) Given that x = e t , show that (i) y dy = e -t , dx dt 2 dy o d2 y – 2t ? d y c 2 – ?. =e c 2 dt ? dx o e dt (ii) (5) (b) Use you answers to part (a) to show that the substitution x = e t transforms the differential equation d2 y dy x 2 2 – 2x + 2y = x3 dx dx into d2 y dy – 3 + 2 y = e 3t . 2 dt dt (3) (c) Hence find the general solution of x2 d2 y dy – 2x + 2y = x3. 2 dx dx (6) END 4 Paper Reference(s) 6668 Edexcel GCE Further Pure Mathematics FP2 Advanced Level Specimen Paper Time: 1 hour 30 minutes Materials required for examination Answer Book (AB16) Graph Paper (ASG2) Mathematical Formulae (Lilac) Items included with question papers Nil Candidates may use any calculator EXCEPT those with the facility for symbolic algebra, differentiation and/or integration. Thus candidates may NOT use calculators such as the Texas Instruments TI 89, TI 92, Casio CFX-9970G, Hewlett Packard HP 48G. Instructions to Candidates In the boxes on the answer book, write the name of the examining body (Edexcel), your centre number, candidate number, the unit title (Further Pure Mathematics FP2), the paper reference (6668), your surname, initials and signature. When a calculator is used, the answer should be given to an appropriate degree of accuracy. Information for Candidates A booklet ‘Mathematical Formulae and Statistical Tables’ is provided. Full marks may be obtained for answers to ALL questions. This paper has eight questions. Advice to Candidates You must ensure that your answers to parts of questions are clearly labelled. You must show sufficient working to make your methods clear to the Examiner. Answers without working may gain no credit. This publication may only be reproduced in accordance with London Qualifications Limited copyright policy. Edexcel Foundation is a registered charity.  ©2003 London Qualifications Limited 1. The displacement x of a particle from a fixed point O at time t is given by x = sinh t. 4 At time T the displacement x = . 3 (a) Find cosh T . (2) (b) Hence find e T and T. (3) 2. Given that y = arcsin x prove that (a) dy = dx (1 – x ) 2 1 , (3) (b) (1 – x 2 ) d2 y dy -x = 0. 2 dx dx (4) Figure 1 3. y P(x, y) s A y O x Figure 1 shows the curve C with equation y = cosh x. The tangent at P makes an angle y with the x-axis and the arc length from A(0, 1) to P(x, y) is s. (a) Show that s = sinh x. (3) (a) By considering the gradient of the tangent at P show that the intrinsic equation of C is s = tan y. 2) (c) Find the radius of curvature r at the point where y = p . 4 (3) S 4. I n = o x n sin x dx. p 2 0 (a) Show that for n ? 2 ?p o I n = nc ? e 2o n -1 – n(n – 1)I n – 2 . (4) (4) (b) Hence obtain I 3 , giving your answers in terms of p. 5. (a) Find ? v(x2 + 4) dx. (7) The curve C has equation y 2 – x 2 = 4. (b) Use your answer to part (a) to fi nd the area of the finite region bounded by C, the positive x-axis, the positive y-axis and the line x = 2, giving your answer in the form p + ln q where p and q are constants to be found. (4) Figure 2 6. y O 2pa x The parametric equations of the curve C shown in Fig. are x = a(t – sin t ), y = a(1 – cos t ), 0 ? t ? 2p . (a) Find, by using integration, the length of C. (6) The curve C is rotated through 2p about Ox. (b) Find the surface area of the solid generated. (5) 7 7. (a) Using the definitions of sinh x and cosh x in terms of exponential functions, express tanh x in terms of e x and e – x . (1) (b) Sketch the graph of y = tanh x. (2) 1 ? 1 + x o lnc ?. 2 e1 – x o (c) Prove that artanh x = (4) (d) Hence obtain d (artanh x) and use integration by parts to show that dx o artanh x dx = x artanh x + 1 ln 1 – x 2 + constant. 2 ( ) (5) 8. The hyperbola C has equation x2 y2 = 1. a2 b2 (a) Show that an equation of the normal to C at P(a sec q , b tan q ) is by + ax sin q = a 2 + b 2 tan q . (6) ( ) The normal at P cuts the coordinate axes at A and B. The mid-point of AB is M. (b) Find, in cartesian form, an equation of the locus of M as q varies. (7) END U Paper Reference(s) 6669 Edexcel GCE Further Pure Mathematics FP3 Advanced Level Specimen Paper Time: 1 hour 30 minutes Materials required for examination Answer Book (AB16) Graph Paper (ASG2) Mathematical Formulae (Lilac) Items included with question papers Nil Candidates may use any calculator EXCEPT those with the facility for symbolic algebra, differentiation and/or integration. Thus candidates may NOT use calculators such as the Texas Instruments TI 89, TI 92, Casio CFX 9970G, Hewlett Packard HP 48G. Instructions to Candidates In the boxes on the answer book, write the name of the examining body (Edexcel), your centre number, candidate number, the unit title (Further Pure Mathematics FP3), the paper reference (6669), your surname, initials and signature. When a calculator is used, the answer should be given to an appropriate degree of accuracy. Information for Candidates A booklet ‘Mathematical Formulae and Statistical Tables’ is provided. Full marks may be obtained for answers to ALL questions. This paper has eight questions. Advice to Candidates You must ensure that your answers to parts of questions are clearly labelled. You must show sufficient working to make your methods clear to the Examiner. Answers without working may gain no credit. This publication may only be reproduced in accordance with London Qualifications Limited copyright policy. Edexcel Foundation is a registered charity.  ©2003 London Qualifications Limited 1. y = x 2 – y, y = 1 at x = 0 . dx y – y0 ? dy o Use the approximation c ?  » 1 with a step length of 0. 1 to estimate the values of y h e dx o 0 at x = 0. 1 and x = 0. 2, giving your answers to 2 significant figures. (6) 2. (a) Show that the transformation w= z -i z +1 maps the circle z = 1 in the z-plane to the line w – 1 = w + i in the w-plane. (4) The region z ? 1 in the z-plane is mapped to the region R in the w-plane. (b) Shade the region R on an Argand diagram. (2) 3. Prove by induction that, all integers n, n ? 1 , ar gt; 2 n r =1 n 1 2 . (7) 4. dy d2 y dy +y = x, y = 0, = 2 at x = 1. 2 dx dx dx Find a series solution of the differential equation in ascending powers of (x – 1) up to and including the term in (x – 1)3. (7) 5. ? 7 6o A=c c 6 2? . ? e o (a) Find the eigenvalues of A. (4) (a) Obtain the corresponding normalised eigenvectors. (6) NM 6. The points A, B, C, and D have position vectors a = 2i + k , b = i + 3j, c = i + 3 j + 2k , d = 4 j + k respectively. (a) Find AB ? AC and hence find the area of triangle ABC. (7) (b) Find the volume of the tetrahedron ABCD. (2) (c) Find the perpendicular distance of D from the plane containing A, B and C. (3) 7. ? 1 x – 1o c ? 5 A( x) = c 3 0 2 ? , x ? 2 c1 1 0 ? e o (a) Calculate the inverse of A(x). (8) ? 1 3 – 1o c ? B = c3 0 2 ? . c1 1 0 ? e o ? po c ? The image of the vector c q ? when transformed by B is cr? e o (b) Find the values of p, q and r. (4) ? 2o c ? c 3? . c 4? e o 11 8. (a) Given that z = e iq , show that zp + 1 = 2 cos pq , zp where p is a positive integer. (2) (b) Given that cos 4 q = A cos 4q + B cos 2q + C , find the values of the constants A, B and C. (7) The region R bounded by the curve with equation y = cos 2 x, rotated through 2p about the x-axis. (c) Find the volume of the solid generated. (6) p p ? x ? , and the x-axis is 2 2 END NO EDEXCEL FURTHER PURE MATHEMATICS FP1 (6667) SPECIMEN PAPER MARK SCHEME Question number 1. Scheme Marks M1 B1 a (r r =1 n 2 – r -1 = a r2 – a r – a1 r =1 r =1 r =1 ) n n n ? n o c a1 = n ? e r =1 o = = = n (n + 1)(2n + 1) – ? 1 on(n + 1) – n c ? 6 e 2o n 2n 2 – 8 6 [ ] M1 A1 A1 (5) (5 marks) 1 n(n – 2 )(n + 2 ) 3 2. (a) f ( x) = ln x – 1 – 1 x f (3) = ln 3 – 1 – 1 = -0. 2347 3 f (4) = ln 4 – 1 – 1 = 0. 1363 4 f (3) and f (4) are of opposite sign and so f ( x ) has root in (3, 4) (b) x 0 = 3. 6 f ? (x ) = 1 1 + x x2 M1 A1 (2) M1 A1 f ? (3. 6 ) = 0. 354 381 f (3. 6) = 0. 003 156 04 Root  » 3. – f (3. 6) f ? (3. 6) M1 A1 ft A1 (5) (7 marks)  » 3. 5911 13 EDEXCEL FURTHER PURE MATHEMATICS FP1 (6667) SPECIMEN PAPER MARK SCHEME Question number 3. Scheme x x x 2 – 3x + 3 1 1 gt; ? gt;0 ? gt;0 x-3 x-2 x-3 x-2 (x – 3)(x – 2 ) Marks M1 A1 B1 B1 Numerator always positi ve Critical points of denominator x = 2, x = 3 x lt; 2 : den = (- ve)(- ve) = + ve 2 lt; x lt; 3 : den = (- ve)(+ ve) = – ve 3 lt; x : den = (+ ve)(+ ve) = + ve M1 A1 A1 (7) (7 marks) Set of values x lt; 2 and x gt; 3 {x : x lt; 2} E {x : x gt; 3} 4. If 1 – 2i is a root, then so is 1 + 2i B1 M1 A1 M1 A1 ft A1 A1 (7) x – 1 + 2i )(x – 1 – 2i ) are factors of f(x) so x 2 – 2 x + 5 is a factor of f (x) f ( x ) = x 2 – 2 x + 5 (2 x – 1) Third root is 1 2 ( ) and p = 12 (7 marks) 5. (a) dS – (0. 1)S = t dt – ( 0. 1)dt Integrating factor e o = e -(0. 1)t M1 d Se – (0. 1)t = te – (0. 1)t dt Se – (0. 1)t = o te – (0. 1)t dt = -10te – (0. 1)t – 100e – (0. 1)t + C [ ] A1 A1 M1 A1 A1 (6) S = Ce (0. 1)t – 10t – 100 (b) S = 200 at t = 0 ? 200 = C – 100 i. e. C = 300 S = 300e (0. 1)t – 10t – 100 M1 A1 At t = 10, S = 300e – 100 – 100 = 615. 484 55 M1 A1 ft (4) (10 marks) Assets ? 615 million NQ EDEXCEL FURTHER PURE MATHEMATICS FP1 (6667) SPECIMEN PAPER MARK SCHEME Question number 6. (a) l Scheme Marks q B1 (Shape) B1 (Labels) (2) (b) Tangent parallel to initial line when y = r sin q is stationary Consider therefore d 2 a cos 2q sin 2 q dq ( ) M1 A1 = -2 sin 2q sin 2 q + cos 2q (2 sin q cos q ) =0 2 sin q [cos 2q cos q – sin 2q sin q ] = 0 sin q ? 0 ? cos 3q = 0 ? q = p -p or 6 6 M1 A1 o ? ? o ? 1 p o? 1 -p Coordinates of the points c c a, ? c a, ? c 6 6 oe 2 e 2 A1 A1 (6) 1 o4 2 1 2o4 (c) Area = o r dq = a o cos 2q dq 2 o -p 2 o -p 4 4 p p M1 A1 a2 a2 1 2 e sin 2q u = a e = [1 – (- 1)] = 2 e 2 u -4p 4 2 u p 4 M1 A1 (4) (12 marks) 15 EDEXCEL FURTHER PURE MATHEMATICS FP1 (6667) SPECIMEN PAPER MARK SCHEME Question number 7. (a) z = -3 + 4i, zw = -14 + 2i Scheme Marks w= = = – 14 + 2i (- 14 + 2i )(- 3 – 4i ) = (- 3 + 4i )(- 3 – 4i ) – 3 + 4i M1 A1 A1 A1 M1 A1 M1 A1 M1 A1 A1 M1 A1 (5) (13 marks) (4) (42 + 8) + i(- 6 + 56) 9 + 16 50 + 50i = 2 + 2i 25 (4) (b) z = (3 2 + 42 = 5 4 = 2. 21 3 ) arg z = p – arctan (c) Equating real and imaginary parts 3m + 14n = 10, 4m + 2n = -20 Solving to obtain m = -6, n = 2 NS EDEXCEL FURTHER PURE MATHEMATICS FP1 (6667) SPECIMEN PAPER MARK SCHEME Question number 8. (a)(i) x = et , dy dy dy dt = = e -t dt dx dt dx Scheme Marks M1 A1 ? dx t o c =e ? e dt o (ii) d 2 y dt d e – t dy u e = dt u dx 2 dx dt e u e M1 e dy d2 yu = e – t e – e -t + e -t 2 u dt dt u e e d 2 y dy u = e – 2t e 2 – u dt u e dt (b) x2 2t A1 A1 (5) d2 y dy – 2x + 2y = x3 2 dx dx – 2t e e e d 2 y dy u t – t dy + 2 y = e 3t e 2 – u, – 2e e dt u dt e dt M1 A1, A1 (3) d2 y dy – 3 + 2 y = e 3t 2 dt dt (c) Auxiliary equation m 2 – 3m + 2 = 0 (m – 1)(m – 2) = 0 Complementary function y = Ae t + Be 2t e 3t 1 Particular integral = 2 = e 3t 3 – (3 ? 3) + 2 2 General solution y = Ae t + Be 2t + 1 e 3t 2 = Ax + Bx 2 + 1 x 3 2 M1 A1 M1 A1 M1 A1 ft 6) (14 marks) 17 EDEXCEL FURTHER PURE MATHEMATICS FP2 (6668) SPECIMEN PAPER MARK SCHEME Question Number 1. cosh 2 T = 1 + sinh 2 T = 1 + 16 25 = 9 9 Scheme Marks M1 A1 (2) M1 A1 A1 ft (3) cosh T =  ± 5 5 = since cosh T gt; 1 3 3 4 5 + =3 3 3 e T = cosh T + sinh T = Hence T = ln 3 2. (5 mar ks) (a) y = arcsin x ? sin y = x M1 cos y dy =1 dx dy 1 1 = = dx cos y 1- x2 M1 A1 (3) (b) d2 y dx 2 = – 1 1- x2 2 ( ) -3 2 (- 2 x ) M1 A1 = x 1- x2 ( ) -3 2 (1 – x ) 2 d2 y dy -x = 1 – x2 x 1 – x2 2 dx dx ( )( ) -3 2 – x 1- ( 1 2 -2 x ) =0 M1 A1 (4) (7 marks) NU EDEXCEL FURTHER PURE MATHEMATICS FP2 (6668) SPECIMEN PAPER MARK SCHEME Question Number 3. Scheme x 0 Marks (a) s=o e ? dy o 2 u 2 e1 + c ? u dx e e dx o u u e dy = sinh x dx 1 y = cosh x, x B1 s = o 1 + sinh 2 x 2 dx 0 [ ] 1 = o cosh x dx = sinh x 0 x M1 A1 (3) (b) Gradient of tangent dy = tan y = sinh x = s dx s = tan y M1 A1 M1 A1 A1 (2) (c) r= ds = sec2 y dy At y = p , r = sec2 p = 2 4 4 (3) (8 marks) 19 EDEXCEL FURTHER PURE MATHEMATICS FP2 (6668) SPECIMEN PAPER MARK SCHEME Question Number 4. Scheme I n = o x n sin x dx = x n (- cos x ) p 2 0 Marks (a) [ ] p 2 0 – o 2 nx n -1 (- cos x )dx 0 p M1 A1 i i = 0 + ni x n -1 sin x i i [ -o 0 p 2 p 2 0 = n (p ) 2 [ n -1 – (n – 1)I n -2 n -1 ] u i (n – 1)x n- 2 sin x dxy i ? A1 So I n = n(p ) 2 2 – n(n – 1)I n -2 A1 (4) (b) ?p o I 3 = 3c ? – 3. 2 I 1 e2o I 1 = o x sin x dx = [x(- cos x )] + o cos x dx 0 p 2 0 p 2 p 2 0 M1 = [sin x ] = 1 0 p 2 A1 3p ? p o I 3 = (3)c ? – 6 = -6 4 e 2o 2 2 M1 A1 (4) (8 marks) OM EDEXCEL FURTHER PU RE MATHEMATICS FP2 (6668) SPECIMEN PAPER MARK SCHEME Question Number 5. Scheme x = 2 sinh t Marks B1 (a) (x 2 + 4 = 4 sinh 2 t + 4 ) ( 2 ) 1 2 = 2 cosh t dx = 2 cosh t dt I =o (x + 4 dx = 4 o cosh 2 t dt ) M1 A1 = 2 o (cosh 2t + 1) dt = sinh 2t + 2t + c M1 A1 M1 A1 ft (7) = 1 x 2 (x 2 2 ? xo + 4 + 2arsinh c ? + c e 2o 2 0 ) (b) Area = o y dx = o 0 (x ) 2 + 4 dx 2 ) M1 e1 =e x e2 = 2 ( xu u e x + 4 u + e 2arsinh u 2u0 u0 e 2 2 1 2 2 8 + 2arsinh (1) 2] = 2 2 + ln 3 + 2 A1 2 + 2 ln[1 + ( 2 ) M1 A1 (4) (11 marks) 21 EDEXCEL FURTHER PURE MATHEMATICS FP2 (6668) SPECIMEN PAPER MARK SCHEME Question Number 6. Scheme 2p 0 Marks (a) s=o e e x + y u dt e u e u  · 2 1  · u2 2 dy  · dx  · = x = a (1 – cos t ); = y = a sin t dt dt s=o 2p 0 M1 A1; A1 2p 0 a (1 – cos t ) + sin 2 t 2 dt = a o 2 p ? 2 sin c 0 2p [ ] 1 [2 – 2 cos t ]2 dt M1 A1, A1 ft (6) 1 = 2a o e ? t ou to ? t , = -4a ecosc ? u = 8a e 2o e e 2 ou 0 1 o2 (b) s = 2p o = 2p o 2p 0 ? yc x + y ? dt c ? e o 1 22 2p  · 2  · 2 2p 0 a 2 (1 – cos t ) 2 dt M1 A1 M1 3 = 8pa 2 o 0 2p 0 ?to sin 3 c ? dt e 2o = 8pa 2 o 2 e t 2 ? t ou e1 – cos c 2 ? u sin 2 dt e ou e 2p 64pa 2 t 2 e 3 t u = 8pa e – 2 cos + cos u = 2 3 2u0 3 e A1 A1 ft (5) (11 mar ks) OO EDEXCEL FURTHER PURE MATHEMATICS FP2 (6668) SPECIMEN PAPER MARK SCHEME Question Number 7. Scheme tanh x = sinh x e x – e – x = cosh x e x + e – x B1 Marks (1) (a) (b) 1 y 0 x -1 B1 B1 (2) (c) artanhx = z ? tanh z = x e z – e-z e z + e -z =x M1 A1 e z – e-z = x e z + e-z ( ) 1 – x )e z = (1 + x )e – z e2z = z= 1+ x 1- x 1 ? 1 + x o lnc ? = artanh x 2 e1- x o M1 A1 M1 A1 1 x dx (4) (d) dz 1 ? 1 1 o 1 = c + ? = dx 2 e 1 + x 1 – x o 1 – x 2 o artanh x dx = (x artanh x ) – o 1 – x = (x artanh x ) + 2 M1 A1 A1 (5) 1 ln 1 – x 2 + constant 2 ( ) (10 marks) 23 EDEXCEL FURTHER PURE MATHEMATICS FP2 (6668) SPECIMEN PAPER MARK SCHEME Question Number 8. Scheme x2 y2 =1 a2 b2 2 x 2 y dy =0 a 2 b 2 dx Marks (a) M1 A1 M1 A1 dy 2 x b 2 b 2 a sec q b = 2 = 2 = dx a 2 y a b tan q a sin q Gradient of normal is then a sin q b a Equation of normal: ( y – b tan q ) = – sin q (x – a sec q ) b x si n q + by = a 2 + b 2 tan q (b) M: A normal cuts x = 0 at y = B normal cuts y = 0 at x = ( ) M1 A1 (6) (a 2 + b2 tan q b ) M1 A1 (a = ( ) a2 + b2 tan q a sin q + b2 a cos q 2 ) A1 e a2 + b2 u a2 + b2 sec q , tan q u Hence M is e 2b e 2a u Eliminating q sec 2 q = 1 + tan 2 q 2 2 ( ) M1 M1 e 2aX u e 2bY u =1+ e 2 e u u ea2 + b2 u ea + b2 u A1 2 4a 2 X 2 – 4b 2Y 2 = a 2 + b 2 [ ] A1 (7) (15 marks) OQ EDEXCEL FURTHER MATHEMATICS FP3 (6669) SPECIMEN PAPER MARK SCHEME Question Number 1. Scheme Marks ? dy o x 0 = 0, y 0 = 1, c ? = 0 – 1 = -1 e dx o 0 ? dy o y1 – y 0 = hc ? ? y1 = 1 + (0. 1)(- 1) = 0. e dx o 0 ? dy o x1 = 0. 1, y1 = 0. 9, c ? e dx o 1 ? dy o y 2 = y1 + hc ? e dx o 1 = (0. 1) – 0. 9 2 B1 M1 A1 ft A1 = -0. 89 = 0. 9 + (0. 1)(- 0. 89) = 0. 811  » 0. 81 z -i ? w( z + 1) = ( z – i ) z +1 M1 A1 (6) (6 marks) 2. (a) w= z (w – 1) = -i – w z= -i-w w -1 -i-w =1 w -1 M1 A1 z =1? i. e. w – 1 = w + i (b) z ? 1? w + i ? w -1 M1 A1 (4) B1 (line) B1 (shading) (2) (6 marks) OR qiea=liEe EDEXCEL FURTHER PURE MATHEMATICS FP3 (6669) SPECIMEN PAPER MARK SCHEME Question Number 3. Scheme For n = 1, LHS =1, RHS = So result is true for n = 1 Assume true for n = k. Then k +1 r =1 Marks 1 2 M1 A1 r gt; 2 k2 + k +1 = = 1 2 1 k + 2k + 1 + 2 2 1 (k + 1)2 + 1 2 2 1 M1 A1 ( ) M1 A1 A1 (7) (7 marks) If true for k, true for k+1 So true for all positive integral n d2 y dy dy +y = x, y = 0, = 2 at x = 1 2 dx dx dx d2 y = 0 +1=1 dx 2 Differentiating with respect to x d 3 y ? dy o d2 y + c ? + y 2 =1 dx 3 e dx o dx 2 4. B1 M1 A1 d3 y dx 3 = -(2) + 0 + 1 = -3 2 A1 x =1 By Taylor’s Theorem y = 0 + 2(x – 1) + = 2(x – 1) + 1 1 2 3 1( x – 1) + (- 3)(x – 1) 3! 2! M1 A1 A1 (7) (7 marks) 1 (x – 1)2 – 1 (x – 1)3 2 2 OS EDEXCEL FURTHER MATHEMATICS FP3 (6669) SPECIMEN PAPER MARK SCHEME Question Number 5. Scheme A – lI = 0 Marks (a) (7 – l ) 6 6 =0 (2 – l ) M1 A1 (7 – l )(2 – l ) – 36 = 0 l2 – 9l + 14 – 36 = 0 l2 – 9l – 22 = 0 (l – 11)(l + 2) = 0 ? l1 = -2, l2 = 11 (b) l = -2 Eigenvector obtained from M1 A1 (4) 6 o ? x1 o ? 0 o ? 7 – (- 2) c ? c ? =c ? c 6 2 – (- 2)? c y 1 ? c 0 ? e oe o e o 3Ãâ€"1 + 2 y1 = 0 ? 2o 1 ? 2o c ? e. g. c ? normalised c – 3? c ? 13 e – 3o e o M1 A1 M1 A1 ft ? – 4 6 o ? x2 o ? 0o c ? c ? =c ? l = 11 c ? c ? c ? e 6 – 9o e y2 o e 0o – 2 x2 + 3 y 2 = 0 ? 3o 1 ? 3o c ? e. g. c ? normalised c 2? c ? 13 e 2 o e o A1 A1 ft (6) (10 marks) 27 EDEXCEL FURTHER PURE MATHEMATICS FP3 (6669) SPECIMEN PAPER MARK SCHEME Question Number 6. (a) AB = (- 1, 3, – 1) ; AC = (- 1, 3, 1) . i j k Scheme Marks M1 A1 AB ? AC = – 1 3 – 1 -1 3 1 = i (3 + 3) + j (1 + 1) + k (- 3 + 3) = 6i + 2 j M1 A1 A1 Area of D ABC = = 1 AB ? AC 2 1 36 + 4 = 10 square units 2 = = = 1 AD . AB ? AC 6 M1 A1 ft (7) (b) Volume of tetrahedron ( ) M1 A1 (2) 1 – 12 + 8 6 2 cubic units 3 ? ?  ® ? ? ® (c) Unit vector in direction AB ? AC i. e. perpendicular to plane containing A, B, and C is 1 n= (6i + 2 j) = 1 (3i + j) 10 40 M1 p = n ? AD = 1 10 (3i + j) ? (- 2i + 4 j) = 1 2 -6+4 = units. 10 10 M1 A1 (3) (12 marks) OU EDEXCEL FURTHER MATHEMATICS FP3 (6669) SPECIMEN PAPER MARK SCHEME Question Number Scheme ? 1 x – 1o c ? A( x ) = c 3 0 2 ? c1 1 0 ? e o 3 o ? – 2 2 c ? Cofactors c – 1 1 x – 1? c 2 x – 5 – 3x ? e o Determinant = 2 x – 3 – 2 = 2 x – 5 ? – 2 1 c A (x ) = c 2 2x – 5 c e 3 -1 Marks 7. (a) M1 A1 A1 A1 M1 A1 M1 A1 (8) -1 1 (x – 1) 2x o ? -5 ? – 3x ? o (b) ? 2o ? po ? – 2 – 1 6 o ? 2o c ? 1c c ? ?c ? -1 1 – 5? c 3? c q ? = B c 3? = c 2 c 4? 1 c 3 cr? 2 – 9? c 4? e o e o e oe o M1 A1 ft M1 A1 = (17, – 13, – 24 ) (4) (12 marks) 29 EDEXCEL FURTHER PURE MATHEMATICS FP3 (6669) SPECIMEN PAPER MARK SCHEME Question Number Scheme zp + Marks 8. (a) 1 1 = e ipq + ipq p z e = e ipq + e -ipq = 2 cos pq ( ) M1 A1 (2) (b) By De Moivre if z = e iq zp + 1 = 2 cos pq zp 4 1o ? 4 p = 1 : (2 cos q ) = c z + ? zo e M1 A1 M1 A1 1 1 1 1 = z 4 + 4 z 3 . + 6 z 2 2 + 4 z. 3 + 4 z z z z 1 o ? 1 o ? = c z 4 + 4 ? + 4c z 2 + 2 ? + 6 z o e z o e = 2 cos 4q + 8 cos 2q + 6 M1 A1 3 8 cos 4 q = 1 cos 4q + 1 cos 2q + 8 2 A1 ft (7) (c) V =p o p 2 p 2 p 2 p 2 y dx = p o 2 p 2 p 2 cos 4 x dx =p o 3o 1 ? 1 c cos 4q + cos 2q + ? dq 8o 2 e8 p M1 A1 ft 1 3 u 2 e1 = p e sin 4q + sin 2q + q u 4 8 u-p e 32 2 M1 A1 ft 3 = p2 8 M1 A1 (6) (15 marks) PM How to cite Edexcel Maths Fp2 Paper, Papers

Brand Equity and Loyalty Management

Question: Discuss about the Brand Equity and Loyalty Management. Answer: Introduction: The term brand exploratory provides an in depth analysis of the reputation, position and the brand image of a company in context to the customers. These factors are highly impactful on the success of any organization (Ju-Pak, 2013). The analysis of these aspects would help in identifying the current position and significance of the company in the customers minds (Roy Banerjee, 2007). Consumer Awareness LEGO is a huge toy manufacturing company which has gained huge fame and recognition in the same field. None of the kids grow older without playing with the LEGO toys and thus the brand awareness of the company is extremely high and widespread. LEGO is famous in a cross generational and global way. Due to its amazing strategies for marketing and promotion, the company has managed to gain the attention of a lot of consumers, making it become a brand having brand recognition and awareness high than Ferrari (Lee et al. 2011). The national tours, the launch of the LEGO movie, the LEGO themed video games and various LEGO products has contributed highly in getting the LEGO toys marketed widely and achieving customer awareness on a very significant manner. The company constantly keeps working for increasing its brand awareness and for getting more customers. The latest step of the company to grab a number of customers was to develop an online selling place for the LEGO toys. The company even developed an interactive platform for communicating with the customers. This made a huge contribution in the companys brand awareness, making it a reputed and renowned brand (Juntunen et al. 2011). Brand association The brand awareness and brand association go hand in hand (Richard et al. 2016). If the brand is highly reputed and known, the brand association is also high. Brand association is the impact of the company on the customers. The company has a huge association in the customers minds due to its interactive and fun games and toys (Chao et al. 2015). If people would hear the word Lego, even today they would imagine the LEGO blocks and the amazing cars and houses that were built by the colorful LEGO blocks. This states that the brand association is quite high where the customers remind of the company due to the amazing and fun toys produces by LEGO. The company constantly keeps on working on the packaging and design of the toys which can leave a deep print of the LEGO products in the customers minds (Alkilani et al. 2013). Competitive positioning Being such an amazing and huge brand, the company enjoys quite a monopoly and his market share in various countries. It is very tough to beat this company in terms of toy production. Along with being the oldest and trustworthy developer of the toys, this company has also been one of the evolving and changing company which adapts new tactics an strategy to compete in the market and sustain with a high market share (Richard Bagozzi, 2011). Companies like Oxford toys, Mega blocks, etc. can be a competition to the company, but the imitative to start online sales, and the company can beat all the competitors and potential threats of the market and secure its position (Alkilani et al. 2013). SWOT analysis The key tool that is being widely considered while analyzing the brand and the strategic approach of the product fits in the SWOT analysis. The SWOT analysis of the brand considers the internal and the external analysis that can be felt towards the acceptance of the product by the consumers. The strengths, weaknesses, opportunities and threats of the Lego Brand can be elaborated as per the competitive advantage and the brand positioning. Strength in the SWOT analysis of the company includes the incorporations of special features that can help to develop young children by initiating the recognition of the key skills and the knowledge regarding a particular event or a product that emphasizes the overall feature of the product. The brand name is very much strong and therefore it has mostly been recognized in more than 55 countries with their products and features, this is an effective feature which can be considered. To demonstrate the modern car, many places use the Automoblox concept that helps to assembly and demonstrate young children. The brand name is so strong and so is the product portfolio of the company which is the benefit when there is a competitive advantage which is met in the global industry. The most attractive among are the tourist destination that includes theme parks through which brand name, can be recognized (Luk et al. 2013). The Lego brand has now even extended its services to the TV, video games and as such the movies which give a tough competition to rivals. Weakness of Lego Brand consists of the limited product which is the main concern, still the company is trying hard to compete with the rivals by applying their strategy in this concern. Intense competition is also the main weakness wherein the high brand rivals have strategies to formulate their goals and occupy the market position in the market that consists in online gaming. The opportunities that the brand has includes competition that can be organized in reputed schools where students get direct assistance when it comes to demonstrate the product with its skills. The brand segments can be considered, whereas diversifying the product segment is important. Branding is the concept that needs to be followed so branding exercises should be the new segment of change (Chao et al. 2015). Threats of the company are majorly the products and the competitors. The competitors include Meccano, VTech, Automoblox and Leapfrog. These are a type of external risks that can be analyzed while taking into view the main objective of the company. Recommendation There are certain solutions that fit around while analyzing the companys position and this shows that a strategic approach to build brand awareness with an idea for marketing mix can be applied. Strong community can be applied while the brand awareness strategies may reveal Legos product channels and the concerned business operations that are essential while using competitive strategy. Marketing mix tools such as promotions, discounts, and coupons creates a greater impact while the online and offline initiatives can be taken that increase the reactions of the consumers such as parents and children (Rappaport, 2008). In the toy market, what seems to be essential is even the financial success that has a predominant factor which impacts the parents to buy toys and this is critically managed by the management team. Conclusion While considering the position of Lego in the market, there was an argument that states that the internal sources of the company is strong, whereas the external factors are failed to be responding to the change in the market condition. The results seems that there is a lack of strategic marketing approach and creating a brand awareness which is felt through competition and brand exploratory. There are issues that are related when it comes to the weaknesses and threats of the company. Whereas, the SWOT analysis presents the companys position and the recommendations that can be applied while creating a strategic glow with brand awareness and technological innovation and creativity. References: Alkilani, K., Ling, K. C. Abzakh, A. A. (2013). The impact of experiential marketing and customer satisfaction on customer commitment in the world of social networks. Asian Social Science, 9(1), 262-270. Chao, R.-F. Wu, T.-C., Yen, W.-T. (2015). The influence of service quality, brand image, and customer satisfaction on customer loyalty for private karaoke rooms in Taiwan. The Journal of Global Business Management, 11(1), 59-67. Juntunen, M., Juntunen, J. Juga, J. (2011). Corporate brand equity and loyalty in B2B markets: A study among logistics service purchasers. Journal of Brand Management, 18(4), 300-311. Ju-Pak, K.H. (2013), Content dimension of Web advertising: a cross-national comparison, International Journal of Advertising, 18, pp. 207-31 Lee, M. S., Hsiao, H. D. Yang, M. F. (2011). The study of the relationships among experiential marketing, service quality, customer satisfaction, and customer loyalty. The International Journal of Organizational Innovation, 3(2), 353-379. Luk S., Chan, W. Li, E. (2013), "The content of internet advertisements and its impact on awareness and selling performance", Journal of marketing management, 18(7/8), pp. 693- 720 Rappaport, S. D. (2008) Lessons from Online Practise: New Advertising Models, Journal of Advertising Research 2007, pp. 135-141, Richard, P. Bagozzi, R. (2011). Implementation of marketing strategy,Journalofmarketing 12(2), pp. 127140 Richard, W. Olshavsky Donald, H. (2010). Importance of marketing strategy? Journal of marketing, 13(2), pp. 93100. Roy, D. Banerjee, S. (2007). Caring strategy for integration of brand identity with brand image. International Journal of Commerce and Management, 17(1/2), 140-148.